A) \[T\cos \theta =Mg\]
B) \[T-Mg\cos \theta =\frac{M{{v}^{2}}}{L}\]
C) The magnitude of the tangential acceleration of the bob \[|{{a}_{T}}|\,=g\sin \theta \]
D) \[T=Mg\cos \theta \]
Correct Answer: B
Solution :
From following figure it is clear that \[T-Mg\cos \theta =\]Centripetal force \[\Rightarrow \] \[T-Mg\cos \theta =\frac{M{{v}^{2}}}{L}\]You need to login to perform this action.
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