A) Ethoxyethane
B) 2-Methoxypropane
C) 1-Methoxypropane
D) 1-Butanol
Correct Answer: A
Solution :
Since a single alkyl halide is formed on treatment with HI, it must be a symmetrical ether i.e., ethoxyethane. \[{{C}_{2}}{{H}_{5}}O{{C}_{2}}{{H}_{5}}+2HI\to 2{{C}_{2}}{{H}_{5}}I+{{H}_{2}}O\]You need to login to perform this action.
You will be redirected in
3 sec