A) 1 : 2
B) 2 : 1
C) 2 : 3
D) 1: 1
Correct Answer: A
Solution :
In \[\Delta ACD,\,\frac{h}{\sin {{67.5}^{o}}}=\frac{AC}{\sin {{90}^{o}}}\] \[\Rightarrow \frac{h}{AC}=\sin {{67.5}^{o}}\]....(i) In\[\Delta ABC,\,\frac{AC}{\sin {{22.5}^{o}}}=\frac{x}{\sin {{45}^{o}}}\Rightarrow \frac{AC}{x}=\sqrt{2}\sin {{22.5}^{o}}\] .....(ii) From (i) and (ii), \[\frac{h}{x}=\frac{1}{2}\].You need to login to perform this action.
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