A) \[\frac{150}{\sqrt{3}}metres\]
B) \[100\sqrt{3}metres\]
C) \[150metres\]
D) \[100metres\]
Correct Answer: D
Solution :
\[d=150\cot \varphi =60m\], Also\[h=60\tan \theta =80m\]. Hence\[x=\sqrt{{{80}^{2}}+{{60}^{2}}}=100m\].You need to login to perform this action.
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