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JEE Main & Advanced Physics Elasticity Question Bank Critical Thinking

  • question_answer
    To break a wire, a force of \[{{10}^{6}}\,N/{{m}^{2}}\] is required. If the density of the material is \[3\times {{10}^{3}}\,kg/{{m}^{3}}\], then the length of the wire which will break by its own weight will be [Roorkee 1979; DPMT 2004]

    A) 34 m   

    B)             30 m

    C)             300 m 

    D)             3 m

    Correct Answer: A

    Solution :

    \[L=\frac{P}{dg}=\frac{6}{3\times {{10}^{3}}\times 10}=\frac{100}{3}=34m\]


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