A) Qa is maximum
B) Qb is maximum
C) Qc is maximum
D) Qa = Qb = Qc
Correct Answer: B
Solution :
Radiated power\[P=A\varepsilon \sigma {{T}^{4}}\] Þ P\[\propto A{{T}^{4}}\] From Wein?s law, \[{{\lambda }_{m}}T=\]constant Þ \[T\propto \frac{1}{{{\lambda }_{m}}}\] \ \[P\propto \frac{A}{{{({{\lambda }_{m}})}^{4}}}\propto \frac{{{r}^{2}}}{{{({{\lambda }_{m}})}^{4}}}\] Þ \[{{Q}_{A}}:{{Q}_{B}}:{{Q}_{C}}=\frac{{{2}^{2}}}{{{(300)}^{4}}}:\frac{{{4}^{2}}}{{{(400)}^{4}}}:\frac{{{6}^{2}}}{{{(500)}^{4}}}\] \ \[{{Q}_{B}}\] will be maximum.
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