A) \[{{10}^{9}}K\]
B) \[{{10}^{7}}K\]
C) \[{{10}^{5}}K\]
D) \[{{10}^{3}}K\]
Correct Answer: A
Solution :
Kinetic energy of the molecules of a gas at a temp. T is \[\frac{3}{2}kT\] \[\therefore \]To initiate the reaction \[\frac{3}{2}kT=7.7\times {{10}^{-14}}J\] \[\Rightarrow \frac{3}{2}\times 1.38\times {{10}^{-23}}T=7.7\times {{10}^{-14}}\Rightarrow T=3.7\times {{10}^{9}}K\].You need to login to perform this action.
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