A) Sodium sulphide
B) Sodium sulphite
C) Sodium sulphate
D) Sodium tetrathionate
Correct Answer: D
Solution :
\[2N{{a}_{2}}{{S}_{2}}{{O}_{3}}+{{I}_{2}}\,\to \,N{{a}_{2}}{{S}_{4}}{{O}_{8}}+2NaI\].You need to login to perform this action.
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