JEE Main & Advanced Physics Current Electricity, Charging & Discharging Of Capacitors / वर्तमान बिजली, चार्ज और कैपेसिटर का निर Question Bank Critical Thinking

  • question_answer
    An ionization chamber with parallel conducting plates as anode and cathode has \[5\times {{10}^{7}}\] electrons and the same number of singly-charged positive ions per\[c{{m}^{3}}\]. The electrons are moving at 0.4 m/s. The current density from anode to cathode is \[4\,\mu A/{{m}^{2}}\].  The velocity of positive ions moving towards cathode is                                                                      [CBSE PMT 1992]

    A)            0.4 m/s                                   

    B)            16 m/s

    C)            Zero                                         

    D)            0.1 m/s

    Correct Answer: D

    Solution :

                       Current density of drifting electrons j = nev \[n=5\times {{10}^{7}}c{{m}^{-3}}=5\times {{10}^{7}}\times {{10}^{6}}{{m}^{-3}}\]. \[v=0.4m{{s}^{-1}},\,e=1.6\times {{10}^{-19}}C\]Þ \[j=3.2\times {{10}^{-6}}A{{m}^{-2}}\] Current density of ions = (4 ? 3.2) ´ 10?6 =\[0.8\times {{10}^{-6}}\frac{A}{{{m}^{2}}}\] This gives v for ions = 0.1 ms?1.


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