A) 2 : 3
B) 1 : 3
C) 3 : 1
D) 3 : 2
Correct Answer: D
Solution :
Let \[p\] be the probability of the other event, then the probability of the first event is \[\frac{2}{3}p.\] Since two events are toally exclusive, we have \[p+\left( \frac{2}{3} \right)\text{ }p=1\Rightarrow p=\frac{3}{5}\] Hence odds in favour of the other are \[3:5-3,\] i.e. \[3:2\].
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