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JEE Main & Advanced Physics Current Electricity, Charging & Discharging Of Capacitors / वर्तमान बिजली, चार्ज और कैपेसिटर का निर Question Bank Critical Thinking

  • question_answer
    The temperature of the cold junction of a thermocouple is \[{{0}^{o}}C\] and temperature of the hot junction is \[{{T}^{o}}C.\] The thermo e.m.f. is given by the relation \[E=AT-\frac{1}{2}B{{T}^{2}}\] (where A = 16 and B = 0.08). The temperature of inversion is [AIIMS 2001]

    A)            \[{{100}^{o}}C\]                  

    B)            \[{{300}^{o}}C\]

    C)            \[{{400}^{o}}C\]                  

    D)            \[{{500}^{o}}C\]

    Correct Answer: C

    Solution :

                       \[m=Z\,it\] Þ \[20\times {{10}^{-3}}=\left( \frac{32}{96500} \right)\times 0.15\times t\] \[=6.7min=6min.42sec.\]


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