A) \[\frac{2i}{5}\]
B) \[\frac{3i}{5}\]
C) \[\frac{4i}{5}\]
D) \[\frac{i}{5}\]
Correct Answer: A
Solution :
Applying Kirchoff's law in mesh ABCDA \[-10(i-{{i}_{1}})-10{{i}_{2}}+20{{i}_{1}}=0\] Þ \[\,3{{i}_{1}}-{{i}_{2}}=i\] .......(i) and in mesh BEFCB \[-\,20\,(i-{{i}_{1}}-{{i}_{2}})+\,10\,({{i}_{1}}+{{i}_{2}})+10{{i}_{2}}=0\] Þ \[3{{i}_{1}}+4{{i}_{2}}=2i\] ......(ii) From equation (i) and (ii) \[{{i}_{1}}=\frac{2i}{5},\,{{i}_{2}}=\frac{i}{5}\]Þ \[{{i}_{AD}}=\frac{2i}{5}\]You need to login to perform this action.
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