A) 0.6
B) 0.2
C) 0.21
D) None of these
Correct Answer: B
Solution :
\[P(\overline{A}\cap \overline{B})=P(\overline{A\cup B})=1-P(A\cup B)\] Since \[A\] and \[B\] are mutually exclusive, so \[P(A\cup B)=P(A)+P(B)\] Hence required probability \[=1-(0.5+0.3)=0.2\].
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