A) 200 W and 0.55 henry
B) 100 W and 0.86 henry
C) 200 W and 1.0 henry
D) 100 W and 0.93 henry
Correct Answer: A
Solution :
For dc, \[R=\frac{V}{i}=\frac{100}{1}=100\,\,\Omega \] For ac, \[Z=\frac{V}{i}=\frac{100}{0.5}=200\,\,\Omega \] \[\because \,\,\,Z=\sqrt{{{R}^{2}}+{{(\omega L)}^{2}}}\]Þ \[200=\sqrt{{{(100)}^{2}}+4{{\pi }^{2}}{{(50)}^{2}}{{L}^{2}}}\] \ \[L=0.55\,\,H\]You need to login to perform this action.
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