A) \[\pi /3\]
B) \[\pi /6\]
C) \[\pi /8\]
D) \[\pi /4\]
Correct Answer: B
Solution :
\[\frac{x\cos \theta }{3\sqrt{3}}+y\sin \theta =1.\] Sum of intercepts = \[3\sqrt{3}\]\[\sec \theta +\text{cosec}\,\theta =f(\theta )\], (say) \[f'\,(\theta )=\frac{3\sqrt{3}{{\sin }^{3}}\theta -{{\cos }^{3}}\theta }{{{\sin }^{2}}\theta \,{{\cos }^{2}}\theta }\]. At \[\theta =\frac{\pi }{6},\,f(\theta )\] is minimum.You need to login to perform this action.
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