question_answer

In the given circuit, with steady current, the potential drop across the capacitor must be                               [IIT-JEE (Screening) 2001]

A)            V

B)            V / 2

C)            V / 3

D)            2V / 3

Correct Answer: C

Solution :

                   Moving anticlockwise from A \[-\,iR-V+2V-2iR=0\] or \[3iR=V\] or \[i=\frac{V}{3R}\] \[{{V}_{A}}-{{V}_{B}}=iR+V-V=iR\] Þ Potential drop across C =\[\frac{V}{3}\]