A) (0, 0)
B) (-2, - 2)
C) (-1, -1)
D) (-1, -2)
Correct Answer: C
Solution :The separate equations of the lines given by \[xy+2x+2y+4=0\] are \[(x+2)(y+2)=0\] or \[x+2=0\], \[y+2=0\]. Solving the equations of the sides of the triangle, we obtain the coordinates of the vertices as \[A(-2,0),\ B(0,-2)\]and \[C(-2,-2)\]. Clearly, \[\Delta ABC\]is a right angled triangle with right angle at C. Therefore the centre of the circum-circle is the midpoint of AB whose coordinates are (-1, -1).
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