A) 27/4 sq. unit
B) 9 sq. unit
C) 27/2 sq. unit
D) 27 sq. unit
Correct Answer: D
Solution :
By symmetry the quadrilateral is a rhombus. So area is four times the area of the right angled triangle formed by the tangent and axes in the Ist quadrant. Now, \[ae=\sqrt{{{a}^{2}}-{{b}^{2}}}\Rightarrow ae=2\] Þ Tangent (in first quadrant) at end of latus rectum \[\left( 2,\frac{5}{3} \right)\] is \[\frac{2}{9}x+\frac{5}{3}\frac{y}{5}=1\] i.e., \[\frac{x}{9/2}+\frac{y}{3}=1\] Area \[=4.\,\frac{1}{2}.\,\frac{9}{2}.3=27\] sq. unit.You need to login to perform this action.
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