JEE Main & Advanced Physics Current Electricity, Charging & Discharging Of Capacitors / वर्तमान बिजली, चार्ज और कैपेसिटर का निर Question Bank Critical Thinking

  • question_answer
                    In the circuit element given here, if the potential at point B, VB = 0, then the potentials of A and D are given as [AMU (Med.) 2002]

    A)            \[{{V}_{A}}=-1.5\,V,\,{{V}_{D}}=+2\,V\]                      

    B)            \[{{V}_{A}}=+1.5\,V,\,{{V}_{D}}=+2\,V\]

    C)            \[{{V}_{A}}=+1.5\,V,\,{{V}_{D}}=+0.5\,V\]                 

    D)            \[{{V}_{A}}=+1.5\,V,\,{{V}_{D}}=-0.5\,V\]

    Correct Answer: D

    Solution :

                       Potential difference between A and B \[{{V}_{A}}-{{V}_{B}}=1\times 1.5\] \[\Rightarrow \,\,\,{{V}_{A}}-0=1.5V\Rightarrow {{V}_{A}}=1.5V\] Potential difference between B and C \[{{V}_{B}}-{{V}_{C}}=1\times 2.5=2.5V\] Þ \[0-{{V}_{C}}=2.5V\Rightarrow {{V}_{C}}=-2.5V\] Potential difference between C and D \[{{V}_{C}}-{{V}_{D}}=-2V\]\[\Rightarrow \,\,\,-2.5-{{V}_{D}}=-2\Rightarrow \,{{V}_{D}}=-0.5V.\]


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