A) 1P
B) 2P
C) 4P
D) 8P
Correct Answer: B
Solution :
In isothermal process \[{{P}_{1}}{{V}_{1}}={{P}_{2}}{{V}_{2}}\] or \[PV={{P}_{2}}\times 4V\] \ \[{{P}_{2}}=\frac{P}{4}\] In adiabatic process \[{{P}_{2}}{{V}_{2}}^{\gamma }={{P}_{3}}{{V}_{3}}^{\gamma }\]Þ \[\frac{P}{4}\times {{(4V)}^{1.5}}={{P}_{2}}{{V}^{1.5}}\]Þ \[{{P}_{3}}=2P\]You need to login to perform this action.
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