A) \[2.6\times {{10}^{-5}}m\]
B) \[2.6\times {{10}^{-4}}m\]
C) \[1.3\times {{10}^{-5}}m\]
D) \[1.3\times {{10}^{-4}}m\]
Correct Answer: C
Solution :
Mass deposited \[m=\text{Density}\times \text{Volume}\,\,\text{of}\,\,\text{the}\,\,\text{metal}\] Þ \[m=\rho \times Ax\]. Also \[m=Zit,\] so \[Zit=\rho Ax\] Þ \[x=\frac{Zi\,t}{A\rho }\]\[=\frac{0.00033\times {{10}^{-3}}\times 1.5\times 20\times 60}{(50\times {{10}^{-4}})\times 9000}=1.3\times {{10}^{-5}}\,m\]
You need to login to perform this action.
You will be redirected in
3 sec
