A) (i) 0.04 m from the flat face; (ii) 0.025 m from the flat face
B) (i) At the same position of the cross mark; (ii) 0.025 m below the flat face
C) (i) 0.025 m from the flat face; (ii) 0.04 m from the flat face
D) For both (i) and (ii) 0.025 m from the highest point of the hemisphere
Correct Answer: B
Solution :
Case (i) When flat face is in contact with paper. \[\frac{{{\mu }_{2}}}{v}-\frac{{{\mu }_{1}}}{u}=\frac{{{\mu }_{2}}-{{\mu }_{1}}}{R}\] where \[{{\mu }_{2}}\]= R. I. of medium in which light rays are going = 1 \[{{\mu }_{1}}\]= R. I. of medium from which light rays are coming = 1.6 u = distance of object from curved surface = ? 0.04 m R = ? 0.04 m. \[\therefore \frac{1}{v}-\frac{1.6}{(-0.04)}=\frac{1-1.6}{(-0.04)}\Rightarrow v=-\,0.04\,m\] i.e. the image will be formed at the same position of cross. Case (ii) When curved face is in contact with paper \[\mu =\frac{Real\ depth\ (h)}{Apparent\ depth\ ({h}')}\] \[\Rightarrow 1.6=\frac{0.04}{{{h}'}}\]\[\Rightarrow {h}'=0.025\,m\] (Below the flat face)You need to login to perform this action.
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