A) 180°? 3A
B) 180° + 2A
C) 90° ?A
D) 180° ? 2A
Correct Answer: D
Solution :
By using \[\mu =\frac{\sin \frac{A+{{\delta }_{m}}}{2}}{\sin \frac{A}{2}}\]\[\Rightarrow \]\[\cot \frac{A}{2}=\frac{\sin \frac{A+{{\delta }_{m}}}{2}}{\sin \frac{A}{2}}\] \[\Rightarrow \frac{\cos \frac{A}{2}}{\sin \frac{A}{2}}=\frac{\sin \frac{A+{{\delta }_{m}}}{2}}{\sin \frac{A}{2}}\] \[\Rightarrow \]\[\sin \,\left( 90{}^\circ -\frac{A}{2} \right)=\sin \,\left( \frac{A+{{\delta }_{m}}}{2} \right)\]\[\Rightarrow {{\delta }_{m}}=180-2A\]
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