A) 2
B) 3
C) 4
D) 5
Correct Answer: B
Solution :
From \[\Delta {{S}_{1}}{{S}_{2}}D,\] \[{{({{S}_{1}}D)}^{2}}={{({{S}_{1}}{{S}_{2}})}^{2}}+{{({{S}_{2}}D)}^{2}}\] \[{{({{S}_{1}}P+PD)}^{2}}={{({{S}_{1}}{{S}_{2}})}^{2}}+{{({{S}_{2}}D)}^{2}}\]You need to login to perform this action.
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