JEE Main & Advanced
Chemistry
GOC
Question Bank
Critical Thinking
question_answer
The following reaction is described as [CBSE PMT 1997] \[\begin{matrix} C{{H}_{3}}{{(C{{H}_{2}})}_{5}} \\ {} \\ {{H}_{3}}C \\ \end{matrix}>\underset{H}{\mathop{\underset{|}{\mathop{C}}\,}}\,-Br\xrightarrow{OH}HO-\underset{H}{\mathop{\underset{|}{\mathop{C}}\,}}\,<\begin{matrix} {{(C{{H}_{2}})}_{5}}C{{H}_{3}} \\ {} \\ C{{H}_{3}}\,\,\,\,\,\,\,\,\,\,\, \\ \end{matrix}\]
A)\[S{{E}^{2}}\]
B)\[S{{N}^{1}}\]
C)\[S{{N}^{2}}\]
D)\[S{{N}^{0}}\]
Correct Answer:
C
Solution :
In this reaction inversion of configuration takes place this is called optical inversion. It is an example of \[S{{N}^{2}}\] reaction (Bimolecular Nucleophillic Substitution).