question_answer

The equivalent resistance between the points P and Q in the network given here is equal to (given \[r=\frac{3}{2}\Omega \]) [AMU (Med.) 2002]

A)            \[\frac{1}{2}\,\,\Omega \]

B)            1 W

C)            \[\frac{3}{2}\,\,\Omega \]

D)            2 W

Correct Answer: B

Solution :

                   The given circuit can be simplifies as follows \[R'=\frac{2r}{3}=\frac{2}{3}\times \frac{3}{2}=1\Omega \].