A) \[{{M}_{2}}=2{{M}_{1}}\]
B) \[{{M}_{2}}>2{{M}_{1}}\]
C) \[{{M}_{2}}<2{{M}_{1}}\]
D) \[{{M}_{1}}<10({{m}_{n}}+{{m}_{p}})\]
Correct Answer: C
Solution :
Due to mass defect (which is finally responsible for the binding energy of the nucleus), mass of a nucleus is always less then the sum of masses of it's constituent particles \[_{10}^{20}Ne\] is made up of 10 protons plus 10 neutrons. Therefore, mass of \[_{10}^{20}Ne\] nucleus \[{{M}_{1}}<10\,({{m}_{p}}+{{m}_{n}})\] Also heavier the nucleus, more is he mass defect thus \[20\,({{m}_{n}}+{{m}_{p}})-{{M}_{2}}>10({{m}_{p}}+{{m}_{n}})-{{M}_{1}}\] or \[10\,({{m}_{p}}+{{m}_{n}})>{{M}_{2}}-{{M}_{1}}\] Þ \[{{M}_{2}}<{{M}_{1}}+10\,({{m}_{p}}+{{m}_{n}})\] Þ \[{{M}_{2}}<{{M}_{1}}+{{M}_{1}}\] Þ \[{{M}_{2}}<2{{M}_{1}}\].
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