A) 100
B) 50
C) 30
D) 20
Correct Answer: A
Solution :
At \[{{V}_{g}}=\,-\,3V,\,{{V}_{p}}=300\,V\] and \[{{I}_{p}}=5mA\] At \[{{V}_{g}}=-1V,\] for constant plate current i.e. \[{{I}_{p}}=5mA\] From \[{{I}_{p}}=0.125\,{{V}_{p}}-7.5\] Þ \[5=0.125{{V}_{p}}-7.5\,\] Þ \[{{V}_{p}}=100V\] \ change in plate voltage \[\Delta {{V}_{p}}=300-100=200V\] Change in grid voltage \[\Delta {{V}_{g}}=-1-(-3)=2V\] So, \[\mu =\frac{\Delta {{V}_{p}}}{\Delta {{V}_{g}}}=\frac{200}{2}=100\]You need to login to perform this action.
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