A) \[\frac{{{\mu }_{0}}}{4\pi }(\sqrt{2})\frac{M}{{{d}^{3}}}\]
B) \[\frac{{{\mu }_{0}}}{4\pi }(\sqrt{3})\frac{M}{{{d}^{3}}}\]
C) \[\left( \frac{2{{\mu }_{0}}}{\pi } \right)\,\frac{M}{{{d}^{3}}}\]
D) \[\frac{{{\mu }_{0}}}{4\pi }(\sqrt{5})\frac{M}{{{d}^{3}}}\]
Correct Answer: D
Solution :
At point P net magnetic field \[{{B}_{net}}=\sqrt{B_{1}^{2}+B_{2}^{2}}\] where \[{{B}_{1}}=\frac{{{\mu }_{0}}}{4\pi }.\frac{2M}{{{d}^{3}}}\]and \[{{B}_{2}}=\frac{{{\mu }_{0}}}{4\pi }.\frac{M}{{{d}^{3}}}\] \[\Rightarrow {{B}_{net}}=\frac{{{\mu }_{0}}}{4\pi }.\frac{\sqrt{5}M}{{{d}^{3}}}\]You need to login to perform this action.
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