11th Class Physics Thermodynamical Processes Question Bank Critical Thinking

  • question_answer
    Heat of neutralization of strong acid against strong base is constant and is equal to [EAMCET 1980; AFMC 1989; DPMT 1991; MP PET 1999; BHU 1999; MP PMT 1995]

    A)                 13.7 kcal              

    B)                 57 kJ

    C)                 \[5.7\times {{10}^{4}}\] J             

    D)                 All of the above

    Correct Answer: D

    Solution :

              \[13.7\,\,kcal=57\,kJ=5.7\times {{10}^{4}}J\].


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