• # question_answer If the co-ordinates of the middle point of the portion of a line intercepted between coordinate axes (3,2), then the equation of the line will be            [RPET 1985; MP PET 1984] A)            $2x+3y=12$                              B)            $3x+2y=12$ C)            $4x-3y=6$                                D)            $5x-2y=10$

Obviously the coordinates of the points A and B are (6, 0) and (0, 4) respectively.            Therefore the equation of line AB is $\frac{x}{6}+\frac{y}{4}=1$                    $\Rightarrow 2x+3y=12$.