A) \[1.6\times {{10}^{19}}\]
B) \[3.1\times {{10}^{19}}\]
C) \[4.8\times {{10}^{19}}\]
D) \[6.2\times {{10}^{19}}\]
Correct Answer: B
Solution :
Total charge supplied \[=1\times 10=10\,C\] \[\because \] 2 electronic charge \[(3.2\times {{10}^{-19}}C)\] liberates one \[C{{u}^{++}}\] ion \ Number of \[C{{u}^{++}}\] ions liberated by 10 C charge \[=\frac{1}{3.2\times {{10}^{-19}}}\times 10\]\[=3.1\times {{10}^{19}}\]
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