A) 15/8
B) 25/4
C) 25/8
D) 25/16
Correct Answer: D
Solution :
Here \[L\equiv x+y=2\]and\[{L}'\equiv 2x-2y=1\]. Equation of y-axis is \[x=0\] Hence the vertices of the triangle are \[A(0,\,2),B\left( 0,-\frac{1}{2} \right)\] and\[C\left( \frac{5}{4},\frac{3}{4} \right)\]. Therefore, the area of the triangle is \[\frac{1}{2}\left| \,\begin{matrix} 0 & 2 & 1 \\ 0 & -\frac{1}{2} & 1 \\ \frac{5}{4} & \frac{3}{4} & 1 \\ \end{matrix}\, \right|=\frac{25}{16}\].You need to login to perform this action.
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