A) 0.51 amp
B) 5.1 amp
C) 0.15 amp
D) 1.5 amp
Correct Answer: D
Solution :
\[i=\frac{{{E}_{1}}+{{E}_{2}}+{{E}_{3}}+.....+{{E}_{n}}}{({{r}_{1}}+{{r}_{2}}+{{r}_{3}}+.......+{{r}_{n}})}\] \[=\frac{1.5({{r}_{1}}+{{r}_{2}}+{{r}_{3}}+......+{{r}_{n}})}{({{r}_{1}}+{{r}_{2}}+{{r}_{3}}+.....+{{r}_{n}})}=1.5A\].
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