A) 64 W
B) 32 W
C) 96 W
D) 16 W
Correct Answer: D
Solution :
\[\because \] \[m=Zit\] or \[i=\frac{m}{Zt}\] For silver voltmeter \[{{i}_{1}}=\frac{{{m}_{1}}}{{{Z}_{1}}t}=\frac{2}{1.118\times {{10}^{-3}}\times 1800}=0.994\,\,amp\] For copper voltameter \[{{i}_{2}}=\frac{{{m}_{2}}}{{{Z}_{2}}t}=\frac{1}{3.294\times {{10}^{-4}}\times 1800}=1.687\,\,amp\] \ Power of circuit \[=V({{i}_{1}}+{{i}_{2}})\]\[=6\times (0.994+1.687)\] \[=6\times 2.681\approx 16\,\,W\]
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