A) 16 W
B) 192 W
C) 36 W
D) 64 W
Correct Answer: B
Solution :
\[\frac{{{i}_{1}}}{{{i}_{2}}}=\frac{15}{5}=\frac{3}{1}\] ? (i) Also \[\frac{H}{t}={{i}^{2}}R\Rightarrow 45={{({{i}_{1}})}^{2}}\times 5\] Þ \[{{i}_{1}}=3\,A\] and from equation (i) \[{{i}_{2}}=1\,A\] So \[i={{i}_{1}}+{{i}_{2}}=4\,A\] Hence power developed in \[12\,\Omega \] resistance \[P={{i}^{2}}R={{(4)}^{2}}\times 12=192\,W\]You need to login to perform this action.
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