JEE Main & Advanced Physics Current Electricity, Charging & Discharging Of Capacitors / वर्तमान बिजली, चार्ज और कैपेसिटर का निर Question Bank Critical Thinking

  • question_answer
    A thermocouple of resistance \[1.6\,\Omega \] is connected in series with a galvanometer of \[8\,\Omega \] resistance. The thermocouple develops and e.m.f. of \[10\mu V\] per degree temperature difference between two junctions. When one junction is kept at \[{{0}^{o}}C\] and the other in a molten metal, the galvanometer reads 8 millivolt. The temperature of molten metal, when e.m.f. varies linearly with temperature difference, will be

    A)            \[{{960}^{o}}C\]                  

    B)            \[{{1050}^{o}}C\]

    C)            \[{{1275}^{o}}C\]               

    D)            \[{{1545}^{o}}C\]

    Correct Answer: A

    Solution :

                       Let the temperature of molten metal is \[{{t}^{o}}C.\] The thermo-emf \[e=10\times {{10}^{-6}}t\,\,volt\] Current in the circuit \[i=\frac{e}{R+{{R}_{G}}}=\frac{{{10}^{-5}}t}{8+1.6}=\frac{{{10}^{-5}}t}{9.6}\,amp.\] But \[i=\frac{V}{{{R}_{G}}}=\frac{8\times {{10}^{-3}}}{8}\] \ \[\frac{{{10}^{-5}}t}{9.6}=\frac{8\times {{10}^{-3}}}{8}\]or \[t=\frac{9.6\times {{10}^{-3}}}{{{10}^{-5}}}={{960}^{o}}C\]


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