A) 2 photon of energy 10.2 eV
B) 2 photon of energy of 1.4 eV
C) One photon of energy 10.2 eV and an electron of energy 1.4 eV
D) One photon of energy 10.2 eV and another photon of 1.4 eV
Correct Answer: C
Solution :
Due to 10.2 eV photon one photon of energy 10.2 eV will be detected. Due to 15 eV photon the electron will come out of the atom with energy (15 - 13.6) = 1.4 eV.You need to login to perform this action.
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