A) \[4\times {{10}^{-8}}mo{{l}^{2}}{{l}^{-2}}\]
B) \[4\times {{10}^{-11}}mo{{l}^{2}}{{L}^{-1}}\]
C) \[4\times {{10}^{-4}}mo{{l}^{2}}{{l}^{-2}}\]
D) \[4\times {{10}^{-15}}mo{{l}^{2}}{{l}^{-2}}\]
Correct Answer: A
Solution :
\[\underset{{{K}_{sp}}}{\mathop{CuBr}}\,\] ⇌ \[\underset{(S)\,\,}{\mathop{C{{u}^{+}}}}\,+\underset{(S)\,\,\,\,}{\mathop{B{{r}^{-}}}}\,\] \[{{K}_{sp}}={{S}^{2}}={{(2\times {{10}^{-4}})}^{2}}=4\times {{10}^{-8}}\frac{mo{{l}^{2}}}{{{l}^{2}}}\]
You need to login to perform this action.
You will be redirected in
3 sec
