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11th Class Physics Thermodynamical Processes Question Bank Critical Thinking

  • question_answer
    The enthalpy of neutralization of \[HCN\] by \[NaOH\] is \[-12.13\,kJ\,mo{{l}^{-1}}\]. The enthalpy of ionisation of \[HCN\] will be [BHU 1997]

    A)                 4.519 kJ

    B)                 45.10 kJ

    C)                 451.9 kJ

    D)                 45.19 kJ

    Correct Answer: D

    Solution :

               \[Q=18.94\times 0.632\times 0.998\times 1000\]                    \[-57.4+x=-12.13\]                                 \[x=45.2\]


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