A) 16/81
B) 1/81
C) 80/81
D) 65/81
Correct Answer: A
Solution :
\[P(\]Minimum face value not less than 2 and maximum face value is not greater than 5) \[=P(2\,\text{or}\,3\,\text{or}\,4\,\text{or}5)=\frac{4}{6}=\frac{2}{3}\] Hence required probability \[={}^{4}{{C}_{4}}{{\left( \frac{2}{3} \right)}^{4}}{{\left( \frac{1}{3} \right)}^{0}}=\frac{16}{81}.\]
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