A) \[\frac{1}{{{x}^{2}}}+\frac{1}{2{{y}^{2}}}=1\]
B) \[\frac{1}{4{{x}^{2}}}+\frac{1}{2{{y}^{2}}}=1\]
C) \[\frac{1}{2{{x}^{2}}}+\frac{1}{4{{y}^{2}}}=1\]
D) \[\frac{1}{2{{x}^{2}}}+\frac{1}{{{y}^{2}}}=1\]
Correct Answer: C
Solution :
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