A) \[{{\left( \frac{3}{4}+\frac{1}{4} \right)}^{12}}\]
B) \[{{\left( \frac{1}{4}+\frac{3}{4} \right)}^{12}}\]
C) \[{{\left( \frac{1}{4}+\frac{3}{4} \right)}^{9}}\]
D) \[{{\left( \frac{3}{4}+\frac{1}{4} \right)}^{9}}\]
Correct Answer: A
Solution :
Mean \[=np=3,\] \[S.D.=\sqrt{npq}=\frac{3}{2}\] \[\Rightarrow q=\frac{npq}{np}=\frac{9}{4\times 3}=\frac{3}{4}\] \[\Rightarrow p=1-\frac{3}{4}=\frac{1}{4}\] Hence binomial distribution is \[{{(q+p)}^{n}}={{\left( \frac{3}{4}+\frac{1}{4} \right)}^{12}}\].
You need to login to perform this action.
You will be redirected in
3 sec
