A) \[\frac{a-b}{a+b}\]
B) \[\frac{b-a}{a+b}\]
C) \[\frac{a+b}{a-b}\]
D) \[\frac{b+a}{b-a}\]
Correct Answer: A
Solution :
Given equation can be written as \[(m+1){{x}^{2}}-\{m(a+b)-(a-b)\}x+c(m-1)=0\]. Roots are equal and of opposite sign. So sum of roots is equal to zero. Þ \[0=m(a+b)-(a-b)\]Þ \[m=\frac{a-b}{a+b}\].You need to login to perform this action.
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