A) - 9
B) 6
C) 9
D) 36
Correct Answer: A
Solution :
Given equation \[{{x}^{2}}-|x|-6=0\] If\[x>0\], \ equation is \[{{x}^{2}}-x-6=0\] Þ \[(x-3)(x+2)=0\] Þ \[x=3,\,x=-2\] Þ \[x=3\] If\[x<0\], \ equation is \[{{x}^{2}}+x-6=0\] Þ \[(x+3)(x-2)=0\] Þ \[x=-3,\,x=2\] Þ \[x=-3\] Hence product of all possible real roots = - 9.You need to login to perform this action.
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