A) \[1.4\times {{10}^{-4}}\]
B) \[8.16\times {{10}^{-4}}\]
C) 0.816
D) 1.4
Correct Answer: B
Solution :
\[Mg{{(OH)}^{2}}\] ⇌ \[\underset{(\text{s})}{\mathop{M{{g}^{2+}}}}\,+\underset{{{(2\text{s})}^{2}}}{\mathop{2O{{H}^{-}}}}\,\] \[{{K}_{sp}}=4{{S}^{3}}\Rightarrow S=\sqrt[3]{\frac{{{K}_{sp}}}{4}}=\sqrt[3]{\frac{1.2\times {{10}^{-11}}}{4}}\] \[S=8.16\times {{10}^{-4}}\]You need to login to perform this action.
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