A) 5 kW
B) 9.72 kW
C) 10 kW
D) 12 kW
Correct Answer: B
Solution :
\[{{P}_{t}}={{P}_{c}}\,\left[ 1+\frac{{{m}^{2}}}{2} \right]=9\,\left[ 1+\frac{{{(0.4)}^{2}}}{2} \right]\] \[=9\,\left[ 1+\frac{0.16}{2} \right]\] (Q m = 40% = 0.4) = 9 (1.08) = 9.72 kWYou need to login to perform this action.
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