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JEE Main & Advanced Physics Ray Optics Question Bank Critical Thinking

  • question_answer
    A square of side \[3cm\] is placed at a distance of \[25cm\] from a concave mirror of focal length \[10cm.\] The centre of the square is at the axis of the mirror and the plane is normal to the axis. The area enclosed by the image of the square is

    A)            \[4c{{m}^{2}}\]                   

    B)            \[6c{{m}^{2}}\]

    C)            \[16c{{m}^{2}}\]                 

    D)            \[36c{{m}^{2}}\]

    Correct Answer: A

    Solution :

                       \[m=\frac{I}{O}=\frac{f}{u-f}=\frac{10}{25-10}=\frac{10}{15}=\frac{2}{3}\]            \[{{m}^{2}}=\frac{{{A}_{i}}}{{{A}_{o}}}\Rightarrow {{A}_{i}}={{m}^{2}}\times {{A}_{o}}\]\[={{\left( \frac{2}{3} \right)}^{2}}\times {{(3)}^{2}}=4\,c{{m}^{2}}\]


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