A) \[\frac{5}{64}\]
B) \[\frac{27}{32}\]
C) \[\frac{5}{32}\]
D) \[\frac{1}{2}\]
Correct Answer: C
Solution :
To get 3 white balls in first 6 draw and then a white again in 7th draws. \[P={}^{6}{{C}_{3}}\times {{\left( \frac{1}{2} \right)}^{3}}\left( \frac{1}{2} \right)\text{ }\left( \frac{1}{2} \right)\Rightarrow P=\frac{5}{32}\].
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