A) 192 kJ
B) 192 J
C) 200 J
D) 132 kJ
Correct Answer: A
Solution :
\[I=\frac{m}{Zt}=\frac{2.68}{\frac{108}{96500}\times 10\times 60}=\frac{2.68}{108}\times \frac{965}{6}\approx 4\,A\] Energy \[={{I}^{2}}Rt={{4}^{2}}\times 20\times 600=192\,\,kJ.\]
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